反转列表的方式

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a = [1,2,3,4,5,6]

a = a[::-1]
print(a)

[6, 5, 4, 3, 2, 1]
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a = [1,2,3,4,5,6]
a.reverse()
print(a)

[6, 5, 4, 3, 2, 1]
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a = [1,2,3,4,5,6]
b = sorted(a,reverse=True)
print(b)

[6, 5, 4, 3, 2, 1]
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a = [1,2,3,4,5,6]
a.sort(reverse=True)
print(a)

[6, 5, 4, 3, 2, 1]

列表取同

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a = [11,22,33]
b = [22,33,44]
c = []
for i in a:                   # 遍历a
    if i in b:                # 判断交集
        c.append(i)
print(c)

print(list(set(a) & set(b)))
print(list(set(a).intersection(set(b))))

[22, 33]
[33, 22]
[33, 22]